M.O.P. (Chapter 16): Full-Street [0,1] No-Fold Game
Posted by AF3
Posted by AF3 posted in Mid Stakes
M.O.P. (Chapter 16): Full-Street [0,1] No-Fold Game
Example 16.1
[0,1] Game #4
"One-Full Street. Neither Player May Fold. There is one bet left. "
Why on earth does the optimal solution containing X betting all hands and Y calling with all hands?
It seems dominated for X to bet with any hand worse than .5
How is it not in X's best interest to bet all hands which are in [0, .5] and then just check the rest and hope Y checks behind?
Edit:
I understand that Y can then "improve" their equity by betting all hands that X would be betting plus the top half of the X hands which X is checking, but this doesn't mean that the strategy of betting only those hands which have a positive (or zero) expectation of betting is not dominated. I mean, this strategy they give as the "solution" for X is actually suggesting that X bets the worst possible hand when X knows that Y will call.
Why is the optimal strategy pair not just:
X bets [0,.5] and checks all other hands
Y bets [0,.75] and checks all other hands
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