Pot odd question, need answer please!
Posted by michaelccc0119
Posted by michaelccc0119 posted in Gen. Poker
Pot odd question, need answer please!
Hey guys, sry if this question is really amateur but I've been confused by this for a while.
I've been reading about pot odds and has been confused about different between using hand odds and hand equity.
Ex: (hero) 4h7h
Flop: AhJcTh disregarding what opponent and lets just assume making a flush gives us the winning hand.
From my research it explains calculating odds in two different ways
1.) Hand odd.
You have 2 hearts. Two more hearts fall on the flop. There are now 47 unseen cards. You have 9 outs (9 out of 13 unseen hearts remaining in the deck) to make your flush on the next card.
Divide 47 by 9 = 5.2
Subtract 1 = 4.2
There must be at least 4.2 bets in the pot for you to call a single bet.
2.) the multiply by 4 and 2 rules to calculate hand equity.
You have two hearts. Two more hearts fall on the flop, so you have 9 outs.
9 x 4 = 36, giving you 36% chance to hit your flush and your opponent a 64% chance to hold up and win with a pair.
64/36 is a little less than 2 to 1. Therefore, it would make sense to call bets slightly higher than half the pot size.
I understand the concept of both and should be both right? but what I'm confused about is why hand odd method req. us to have 4.2:1 to call on flop while hand equity only requires us to have 2:1 to call.
thanks.
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