At the top of page 121, we come to the following equation when solving for the optimal strategy pairs in the [0,1] Game # 2:

Let A= Alpha

Let  y = y1

2y = (1 -Ay)(1-A)

Expanding the right hand side gives the following:

2y = (1-Ay)(1-A) = (1*1 - 1*A - Ay*1 - (Ay)*(-A)) = 1 -A - AY - (Ay)(-A)

The authors claim this gives:

2y = 1 - Ay - A + A2y 

How is (-Ay)(-A) equal to A2y?  It seems this should be (A^2)(y)